Question

please solve this 3 ques please help me ya...​

Answer 1

Step-by-step explanation:

let the smallest integer be x

then,

three consecutive integer will be

X , ( x + 1 ), and ( x + 2 )

Now,

(2 × X) + { 4 × ( x+ 1)} + { 6 × ( x + 2)} = 160

= 2x + 4x + 4 + 6x + 12 = 160

= 12x + 16 = 160

= 12x = 144

= x = 144/12

= x = 12

so, three consecutive intezers are X , ( x + 1 ), and ( x + 2 ) = 12 , 13 and 14

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