Please solve this............
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angle in a straight line is 180
2x-30+x-20+x+50=180
4x=180
x=180/4
2x-30+x-20+x+50=180
4x=180
x=180/4
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♧♧HERE IS YOUR ANSWER♧♧
We know that :
<AOB = 180°
=> <AOP + <POQ + <QOB = 180°
=> (2x - 30) + (x - 20) + (x + 50) = 180
=> 4x = 180
=> x = 45
Therefore, x = 45° and the angles are
<AOP = 60°, <POQ = 25° and <QOB = 95°.
♧♧HOPE THIS HELPS YOU♧♧
We know that :
<AOB = 180°
=> <AOP + <POQ + <QOB = 180°
=> (2x - 30) + (x - 20) + (x + 50) = 180
=> 4x = 180
=> x = 45
Therefore, x = 45° and the angles are
<AOP = 60°, <POQ = 25° and <QOB = 95°.
♧♧HOPE THIS HELPS YOU♧♧
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