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∆AOC =∆COD=∆ODB [.°. AOB MAKES 180° OD AND CO DIVIDES EQUALLY]
∆ECD=EQUILATERAL TRIANGLE[.°.each angle 90°]
hence, angle AEB =60°
∆ECD=EQUILATERAL TRIANGLE[.°.each angle 90°]
hence, angle AEB =60°
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