Question

please solve this. ​

Answer 1

☯︎ Aɴsᴡᴇʀ

we have,

• ABCD is a rhombus
• ∠BAC = 48°

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★ firstly we have to know some properties of a rhombus

• both pair of opposite sides of a rhombus are parallel.
• all sides of a rhombus are equal to each other.
• opposite angles are equal
• diagonals of a rhombus bisect each other at 90°

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AB || DC ( opposite sides of rhombus)

here, AB is transversal line.

➪ ∠BAC = ∠DCA (alternate angles)

• ∠BAC = 48°
• ∠DCA = y°

➪ y° = 48°

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in ∆DAC

AD = DC (all sides of a rhombus are equal or adjacent side)

➪ ∠DAC = ∠DCA (angle opposite to equal sides are equal)

➪ ∠DCA = y° = 48°

now, in ∆DAC

∠DAC + ∠DCA + ∠ADC = 180°

( angle sum property : sum of all interior angles of a triangle is 180°)

➪ 48° + 48° + x° = 180°

➪ 96° + x° = 180°

➪ x° = 180° - 96°

➪ x° = 84°

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therefore, value of

• x° is 84°
• y° is 48°