Question

please solve this.......​

Answer 1

$1.(5a - b - c )- (2a + 3b - 5c) \\ = 5a - b - c - 2a - 3b - 5c \\ = 3a - 4b - 6c$

Answer 2

$\Large{\underbrace{\sf{\orange{Required\:Solution:}}}}$

(a) 2α + 3b - 5c from 5α - b - c

Sol'n. (5α - b - c) - (2α + 3b - 5c)

• Open the brackets and multiply (-) with the 2nd bracket.

$\longrightarrow$ 5α - b - c - 2α - 3b + 5c

• subtract the terms with same variables.

$\longrightarrow$ 5α - 2α -b - 3b - c + 5c

$\large\implies{\boxed{\sf{\orange{3α - 4b + 4c}}}}$

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(b) x³ - 3x² + x - 5 from 1 - 7x^4 - 2x

Sol'n. $\displaystyle{\sf{(1-7x^{4}-2x)-(x^{3}-3x^{2}+x-5)}}$

• Open the brackets and multiply the (-) sign over the second bracket.

$\longrightarrow{\sf{1-7x^{4}-2x-x^{3}+3x^{2}-x+5}}$

• Subtract the terms having same variable and exponents.

$\longrightarrow{\sf{-7x^{4}-2x-x-x^{3}+3x^{2}+5+1}}$

$\large\implies{\boxed{\sf{\orange{-7x^{4}-3x-x^{3}+3x^{2}+6}}}}$

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(c) p²q - pq² + 3p - q from 5p - 2q - p²q - pq²

Sol'n. $\displaystyle{\sf{(5p-2q-p^{2}q-pq^{2})-(p^{2}q-pq^{2}+3p-q)}}$

• Open the brackets and multiply the (-) sign over the second bracket.

$\longrightarrow{\sf{5p-2q-p^{2}q-pq^{2}-p^{2}q+pq^{2}-3p+q}}$

• Subtract the terms having same variable and exponents.

$\longrightarrow{\sf{5p-3p-2q+q-p^{2}q+p^{2}q-pq^{2}+pq^{2}}}$

$\large\implies{\boxed{\sf{\orange{2p-q}}}}$

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