please solve this ...........
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kya question hhhhhh......
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Construction: Join BD
In △ABD, PO∥AB [∵ PQ∥AB ]
⇒ APDP=OBDO [ By basic proportionality theorem ] ------ ( 1 )
⇒ In △BDC, OQ∥DC [
∵ PQ∥DC ]
QC/BQ=OD/OB [ By basic proportionality theorem ]
⇒ BQ/QC=OB/OD ----- ( 2 )
⇒ AP/DP=BQ/QC [ From ( 1 ) and ( 2 ) ]
⇒ AP/18=35/15
∴ AP=(18×35)/15=42
∴ AD=AP+DP=42+18=60cm.
hope this will help u
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