please solve this 327^2-326^3
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-34539047 is the answer
Answered by
1
Answer:
For this one, you need to consider that 2^372 = 2 * 2^326. So, we would have:
2^327 - 2^326 = 2 * 2^326 - 2^326
Factoring out 2^326, we get:
2^326 ( 2 - 1 ) = 2^326.
Therefore, 2^327 - 2^326 = 2^326.
So, then, we out the log = x. So:
log_2 (2^326) = x
Rewriting it as an exponential, we get:
2^x = 2^326.
So, x has to be 326.
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