Question

Please solve this ⬆️⬆️

Answer 1

Hi ,

Quantity of the milk in first container = 398l

Quantity of the milk in second container = 436l

after transferred to another containers.

remaining milk in the containers 7l and 11l

quantity transferred in first container = ( 398 - 7 )

= 391 l

second container = ( 436 - 11 ) = 425 l

find the HCF of 391 and 425 ,

391 ) 425 ( 1
*******391
________
********34) 391(11
************374
_____________
**************17)34( 2
*****************34
_______________

Therefore ,

HCF ( 391 , 425 ) = 17

1 ) maximum capacity of the drum = 17 l

Answer 2

Hope it helps !.................. .