Question

Please solve this ;-

Answer 1

★ Hi there !!! ★


here is your answer !!


look this attachment :-



hope it helps !!


hence , the sum = 4


and Product is ==> 1





thanks !!!

Answer 2

Answer :

The sum and product of two zeroes of the given polynomial are 0 and (- 9) respectively.

So, one factor be

= x² - (0 × x) + (- 9)

= x² - 9

Now, since (x² - 9) is a factor of the given polynomial (x^4 - 4x³ - 8x² + 36x - 9), we can write

x^4 - 4x³ - 8x² + 36x - 9

= x^4 - 9x² - 4x³ + 36x + x² - 9

= x²(x² - 9) - 4x(x² - 9) + 1(x² - 9)

= (x² - 9)(x² - 4x + 1)

[N.B. - This method is called zero-putting method]

Thus, we get another factor (x² - 4x + 1).

So, the sum and product of the other two zeroes are {- (-4)/1} = 4 and 1 respectively.

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