Question

Please solve this ;-

Answer 1

hey dear friend here's ur answer ....

32)

f(x) = x3-5x+6x-4

q(x) = x-3

r(x) = -3x+5

g(x) = ?

Now,

f(x) = g(x).q(x)+r(x)

So, g(x) = f(x)-r(x) / q(x)

g(x) = x3-5x2+6x-4-(-3x+5) / x-3

g(x) = x3-5x2+9x-9 / x-3

g(x) = x2-2x+3

33)

ohh !! I'm sorry dear but my answer was not coming when I tries it in copy ...I'm so so so sorrrry

Answer 2

Final Answer : 32 :
$g(x) = {x}^{2} - 2x + 3$




33 : All zeroes are √3i, -√3i, 1
where i is iota = √(-1)

For Calculation see pic.