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Answered by
6
a2-a1 = a3-a2
2k-1 - (k+9) = 2k+1-(2k-1)
2k-1-k-9=2k+1-2k+1
k - 10 = 2
k =2+10
k=12
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Answered by
2
Answer:
let k+9=a
2k-1=b
2k+7=c
to be in Ap
a+b=2b
k+9+2k+7-2 (2k-1)
3k+16=4k-2
3k-4k=-2-16
-k= -18
k=18
for k=18, the terms k+9, 2k-1, 2k+7 are in Ap
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