Math, asked by Anonymous, 4 months ago

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Answered by saiyedfazil
6

a2-a1 = a3-a2

2k-1 - (k+9) = 2k+1-(2k-1)

2k-1-k-9=2k+1-2k+1

k - 10 = 2

k =2+10

k=12

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Answered by yeojuda
2

Answer:

let k+9=a

2k-1=b

2k+7=c

to be in Ap

a+b=2b

k+9+2k+7-2 (2k-1)

3k+16=4k-2

3k-4k=-2-16

-k= -18

k=18

for k=18, the terms k+9, 2k-1, 2k+7 are in Ap

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