Question

please solve this.,....

Answer 1

$= > \: {(81)}^{x} = \frac{1}{ {(125)}^{y} } \\ \\ = > {(3)}^{4x} = \frac{1}{( {5)}^{3y} } \\ \\ = > {(3)}^{4x} \times {(5)}^{3y} = 1 \\ \\ = > {(3)}^{4x} \times {(5)}^{3y} = {(3)}^{0} \times {(5)}^{0} \\ \\ = > 4x \: = 0 \: \: ...........Eq _{1} \\ \\ = > 3y \: = 0...........Eq _{2} \\ \\ By \: \ Eq _{1} \: and \: Eq _{2} \: we \: get \\ \\ = > 12xy \: = 0 _____Answer$

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Answer 2

Explanation:

ᴡʜᴀᴛ ᴛᴏ ғɪɴᴅ ʜᴇʀᴇ?????????