Please solve this .....
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ck233:
hi
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HEYA!!!! YOUR ANSWER IS HERE....
.
Initial Speed Of Rail = 0=V1
Mass Of Rail= M1 = 100 kg
Speed Of Boy = 5 m/s = V2
Mass of Boy = 40 kg = M2
By Law Of Conservation Of Momentum
.
5*40 = V2( 100+40)
200 = V2 ( 140)
V2 = 200/140
V2 = 1.4 m/s
.
HOPE IT HELPS YOU, DEAR....
.
Initial Speed Of Rail = 0=V1
Mass Of Rail= M1 = 100 kg
Speed Of Boy = 5 m/s = V2
Mass of Boy = 40 kg = M2
By Law Of Conservation Of Momentum
.
5*40 = V2( 100+40)
200 = V2 ( 140)
V2 = 200/140
V2 = 1.4 m/s
.
HOPE IT HELPS YOU, DEAR....
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