Question

please solve this.
:-)​

Answer 1

Answer:

b. 5389/2319

c. 5715/7150

d. 49/8

e. 453/252

f. 19/39

Step-by-step explanation:

according to BODMAS rule

(b)

$</p><p>[tex]\frac{2}{3} \div \frac{4}{7} + 1 \frac{2}{5} - \frac{3}{7} of \frac{6}{11} \\ = \frac{2}{3} \div \frac{4}{7} + \frac{7}{5} - \frac{18}{77} \\ = \frac{2}{3} \times \frac{7}{4} + \frac{7}{5} - \frac{18}{77} \\ = \frac{7}{6} + \frac{7}{5} - \frac{18}{77} \\ = \frac{77}{30} - \frac{18}{77} \\ = \frac{(77 \times 77 ) - (30 \times 18)}{30 \times 77} \\ = \frac{5929 - 540}{2310} \\ = \frac{5389}{2310}$

[/tex]

(c)

$</p><p>[tex]frac{4}{5} of \frac{9}{13} + \frac{6}{11} - \frac{3}{2} \times \frac{1}{5} \\ = \frac{36}{65} + \frac{6}{11} - \frac{3}{2} \times \frac{1}{5} \\ = \frac{36}{65} + \frac{6}{11} - \frac{3}{10} \\ = \frac{36}{65} + \frac{27}{110} \\ = \frac{5715}{7150}$

[/tex]

(d)

$</p><p>[tex]1 \frac{3}{4} \times (2 \frac{2}{3} + (( \frac{5}{6} - \frac{2}{3} ) \div \frac{2}{5} of \frac{1}{2} )) \\ = \frac{7}{4} \times ( \frac{8}{3} + (( \frac{1}{6} ) \div \frac{2}{5} of \: \frac{1}{2} )) \\ = \frac{7}{4} \times ( \frac{8}{3} + ( \frac{1}{6} \div \frac{1}{5} )) \\ = \frac{7}{4} \times ( \frac{8}{3} + \frac{5}{6} ) \\ = \frac{7}{4} \times \frac{21}{6} \\ = \frac{49}{8}$

[/tex]

(e)

$(2\frac{1}{2} + ((1 \frac{1}{6} - \frac{2}{3} of \frac{4}{5} ) \div \frac{1}{2} )) \times \frac{5}{7} \\ = ((\frac{5}{4} + (( \frac{7}{6} - \frac{8}{15} ) \div \frac{1}{2} )) \times \frac{5}{7} \\ = (\frac{5}{4} + (\frac{57}{90} \times 2)) \times \frac{5}{7} \\ = ( \frac{5}{4} + \frac{57}{45} ) \times \frac{5}{7} \\ = \frac{ 453 }{180} \times \frac{5}{7 } \\ = \frac{453}{252}$

(f)

$\frac{6}{13} of((( \frac{5}{6} + \frac{2}{3} ) - ( \frac{2}{5} \div \frac{1}{2} ) \times \frac{5}{9} )) \\ = \frac{6}{13} of(\frac{3}{2} - ( \frac{2}{5} \times 2) \times \frac{5}{9} ) \\ = \frac{6}{13} of( \frac{3}{2} - \frac{4}{5} \times \frac{5}{9} ) \\ = \frac{6}{13} of( \frac{3}{2} - \frac{4}{9} ) \\ = \frac{6}{13} of \frac{19}{18} \\ = \frac{19}{39}$