Question

Please solve this.. 5 question fast..

Answer 1

Answer:

Step-by-step explanation:

Angle A+ Angle B + Angle C + Angle D = 360

So,

Angle A + Angle B = 360-160=200

Then ,

In triangle ARB ,

Angle ARB + Angle RAB + Angle ABR = 180

Angle RAB + Angle ABR = 200/2 =100

Angle ARB = 180-100 = 80

So, the answer is 80 degree

Answer 2

Answer:

∠ARB = 80°

Step-by-step explanation:

From figure:

We know that Sum of Quadrilateral is 360°

⇒ ∠A + ∠B + ∠C + ∠D = 360°

⇒ ∠A + ∠B + 110 + 50 = 360°

⇒ ∠A + ∠B = 360 - 160

⇒ ∠A + ∠B = 200.

According to the given condition,

⇒ ∠RAB + ∠RBA + ∠ARB = 180°

⇒ ∠DAB/2 + ∠CAB/2 + ∠ARB = 180°

⇒ (∠A + ∠B)/2 + ∠ARB = 180°

⇒ 200/2 + ∠ARB = 180°

⇒ 100 + ∠ARB = 180°

⇒ ∠ARB = 180° - 100°

⇒ ∠ARB = 80°

Hope it helps!