Question

please solve this.50 points for this answer and NO SPAMMING PLEASE​

Answer 1

$\begin{aligned}&4^x-4^{x-1}=24\\\\\implies\ \ &4^{x-1}(4-1)=24\\\\\implies\ \ &4^{x-1}\cdot3=8\cdot3\\\\\implies\ \ &(2^2)^{x-1}=8\\\\\implies\ \ &2^{2x-2}=2^3\\\\\implies\ \ &2x-2=3\\\\\implies\ \ &\boxed{\mathbf{x=\dfrac{5}{2}}}\end{aligned}$

Answer 2

Answer:

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