Question

Please solve this !!

Answer 1

I think 25 is correct

Answer 2

Answer:

(C) 25°

Step-by-step explanation:

Given: ABCD is a quadrilateral and ∠ABC=70°, FG bisects ∠CFA and EG bisects ∠DEB, also ∠DCE= 60°.

To find: ∠HEC

Proof: In ΔBCF, ∠BCF=60° ( Vertically opposite angle)

Using the exterior angle property in ΔBCF, we have

∠CBA=∠BCF+∠CFB

⇒70°=60°+∠CFB

⇒∠CFB=10°

Now, FG bisects ∠CFA, therefore ∠CFG=∠GFB

⇒∠CFG=5°

From ΔHGF, ∠HGF+∠GHF+∠HFG=180°(Sum of all the nagles of triangle =180°)

⇒∠GHF=85°

Again, using exterior angle property in triangle HEC, we have

∠CHG=∠HEC+∠ECH

⇒85°=∠HEC+60°

⇒∠HEC=25°