Question

please solve this.................

Answer 1

10√2
none of these
hope this will help

Answer 2

Hey here is your answer ⤵⤵⤵⤵

Given one side of the rhombus =1O cm
and one of the diagonal =12cm

Let the rhombus be ABCD and diagonals intersect at O

Since diagonals of a rhombus bisect each other , OB=1/2DB =>OB=1/2 × 12=6cm

Now using pythagoras Pythagorean theorem we get

⏩⏩
${bc}^{2} = {ob}^{2} + {oc}^{2}$

⏩⏩
${10}^{2} = {6}^{2} + {oc}^{2}$

⏩⏩
$100 - 36 = {oc}^{2}$

⏩⏩
$64 = {oc}^{2}$

⏩⏩
$\sqrt{64} = oc$

⏩⏩
$8 = oc$
Now

BD=2OC
=2×8
=16 cm ✔✔

❤hope it helps you❤

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