please solve this......................
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3sin theta cos theta= 1.............
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Tanθ + Cotθ = 3
Squaring on both sides we get :
(Tanθ + Cotθ)² = 9
Tan²θ + Cot²θ + 2 × Tanθ × Cotθ = 9
We know that Tanθ = 1/Cotθ
⇒ Tanθ × Cotθ = 1
⇒ Tan²θ + Cot²θ + 2 = 9
⇒ Tan²θ + Cot²θ = 7
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