Please solve this!!!!
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it's answer should be 2b
srishapoddar:
how?
1b distance in left side of 0 axis and 1b distance on other side
reason?
oh okay thanks
plz mark my answer brainliest
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(0,b) is a point on y=b and (0,-b) is a point on y= -b therefore distance =√[(0-0)^2+{b-(-b)}^2]
=√{0+(2b)^2}=√(2b)^2=2b unit
=√{0+(2b)^2}=√(2b)^2=2b unit
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