please solve this 6th and 7th question. please no spam.
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6. Given that AP=3cm
PB=6cm
AQ=5cm
QC=10cm
To show that BC=3PQ.
We can show this by using the converse of basic proportionality theorem.
AP/AB = AQ/AC
⇒3/3+6 =5/5+10
⇒3/9=5/15
⇒1/3=1/3
Since they are equal proportions, thus, PQ is parallel to BC
And,
AP/AB=AQ/AC=PQ/BC
⇒5/15=PQ/BC
⇒1/3=PQ/BC
∴BC=3PQ
Hence proved
7. is above
PB=6cm
AQ=5cm
QC=10cm
To show that BC=3PQ.
We can show this by using the converse of basic proportionality theorem.
AP/AB = AQ/AC
⇒3/3+6 =5/5+10
⇒3/9=5/15
⇒1/3=1/3
Since they are equal proportions, thus, PQ is parallel to BC
And,
AP/AB=AQ/AC=PQ/BC
⇒5/15=PQ/BC
⇒1/3=PQ/BC
∴BC=3PQ
Hence proved
7. is above
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sahil043:
sir AP=3.5 cm
hlo AP=3.5 cm, PB=7cm, AQ=3cm, QC = 6cm and PQ=4.5cm
this is wrong
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aq/ac=ap/ab = qp/bcBPT
ac=6+3=9
ab=3.5+7=10.5
3/9=4.5/bc
bc=4.5*9/3
=4.5*3=13.5
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