Question

please solve this 6th and 7th question. please no spam.

Answer 1

6. Given that AP=3cm

PB=6cm

AQ=5cm

QC=10cm

To show that BC=3PQ.

We can show this by using the converse of basic proportionality theorem.

AP/AB = AQ/AC

⇒3/3+6 =5/5+10

⇒3/9=5/15

⇒1/3=1/3 

 Since they are equal proportions, thus, PQ is parallel to BC

And,

AP/AB=AQ/AC=PQ/BC

⇒5/15=PQ/BC

⇒1/3=PQ/BC

∴BC=3PQ 

Hence proved
7. is above

Answer 2

aq/ac=ap/ab = qp/bcBPT

ac=6+3=9

ab=3.5+7=10.5

3/9=4.5/bc

bc=4.5*9/3

=4.5*3=13.5

Hope it helps...