Question

please solve this 7th , 8th questions

Answer 1

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Answer 2

Hi friends

Here is your answer
P = 31250
A = 35152
T =1 1/2 years
n = 3 as it is semi annually

As we know
A = P(1+R/100)^n
$35152 = 31250(1 + \frac{r}{100}) {}^{3} \\ \\ \frac{35152}{31250} = ( \frac{100 + r}{100} ) {}^{3} \\ \\ \frac{17576}{15625} = ( \frac{100 + r}{100} ) {}^{3} \\ \\ ( \frac{26}{25} ) {}^{3} = ( \frac{100 + r}{100} ) {}^{3} \\ \\ \frac{26}{25} = \frac{100 + r}{100} \\ \\ 26 \times 100 = 25(100 + r) \\ \\ 2600 - 2500 = 25r \\ \\ 25r = 100 \\ r = \frac{100}{25} \\ \\ r = 4\%$
Hence R = 4%

Hope it helps you
@MSD