Question

please solve this ...............................................​

Answer 1

Answer:

This will be much tidier if we just write

x = cos θ   and    y = sin θ

Then     sec θ = 1 / x    and    cosec θ = 1 / y.

Now the LHS is...

$\displaystyle\frac1{1+y^2}+\frac1{1+x^2}+\frac1{1+\frac1{x^2}}+\frac1{1+\frac1{y^2}}\\\\=\frac1{1+y^2}+\frac1{1+x^2}+\frac{x^2}{x^2+1}+\frac{y^2}{y^2+1}\\\\=\frac{1+y^2}{1+y^2}+\frac{1+x^2}{1+x^2}\\\\=1+1\\=2$

Answer 2

Heya

______________________________

We know that Sec x = 1/Cos x And

Cosec x = 1/Sin x

=>

1/(1+ Sin²x ) + 1(1 + Cos² x ) + Cos² x / ( 1 + Cos² x ) + Sin² x / ( 1 + Sin² x )

=>

1 + 1 = 2