Math, asked by Sayilesh, 1 year ago

Please Solve This! ​

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Answered by helpinghand07
1

3/5  Sin A  + 4/5  Cos A  = 1

we see that  (3/5)² + (4/5)² = 1

let  3/5 = Sin B            and      4/5 = Cos B

 So Sin A Sin B + Cos A Cos B = 1 = Cos 0°

       Cos (A - B) = cos 0°

       A = B    or    A - B = 2 π

   if A = B,  Sin A = Sin B = 3/5.

 or,  if A - B = 2π,  Sin A = Sin (2π+B) = Sin B = 3/5

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