Math, asked by gangurdesnehal96, 7 months ago

PLEASE SOLVE THIS:
A passenger train takes 2 hours more than an express train to travel a distance of 240 km from Vardha to Akola. The speed of the passenger train is less than that of express train by 20km/hr. Find the average speed of both trains.​

Answers

Answered by sri2011
2

Answer:

50km/hr

Step-by-step explanation:

Let speed of passenger train = x km/hr

Let speed of express train = y km/hr

Given that, speed of the passenger train is less than that of express train by 20km/hr.

i.e. x=y-20

x+20=y ---eq1

Distance = 240 km

Time taken by passenger train = t1

Time taken by express train = t2

we know that,

Speed = Distance/Time

Therefore, for passenger train,

x = 240/t1

t1=240/x

for express train,

y = 240/t2

t2 = 240/y

Given that, passenger train takes 2 hours more than an express train

i.e. t1 = t2+2

240/x = 240/y + 2

240/x = 240/x+20 + 2      (from eq 1)

240(x+20) = 240x + 2x(x+20)

120(x+20) = 120x + x^2 +20x

120x + 2400 = 120x + x^2 + 20x

x^2 + 20x - 2400 = 0

x^2 + 60x - 40x - 2400 = 0

x(x+60) - 40(x+60) = 0

x = 40,-60

As speed cannot be negative,

x=40km/hr

Speed of passenger train = x= 40km/hr

Speed of express train = y = x+20

                                            = 40+20

                                            = 60km/hr

Average speed of both trains = (x+y)/2

                                                 = (40+60)/2

                                                 =50km/hr

                                                   

Answered by NetraJ7
6

Answer:

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