PLEASE SOLVE THIS:
A passenger train takes 2 hours more than an express train to travel a distance of 240 km from Vardha to Akola. The speed of the passenger train is less than that of express train by 20km/hr. Find the average speed of both trains.
Answers
Answer:
50km/hr
Step-by-step explanation:
Let speed of passenger train = x km/hr
Let speed of express train = y km/hr
Given that, speed of the passenger train is less than that of express train by 20km/hr.
i.e. x=y-20
x+20=y ---eq1
Distance = 240 km
Time taken by passenger train = t1
Time taken by express train = t2
we know that,
Speed = Distance/Time
Therefore, for passenger train,
x = 240/t1
t1=240/x
for express train,
y = 240/t2
t2 = 240/y
Given that, passenger train takes 2 hours more than an express train
i.e. t1 = t2+2
240/x = 240/y + 2
240/x = 240/x+20 + 2 (from eq 1)
240(x+20) = 240x + 2x(x+20)
120(x+20) = 120x + x^2 +20x
120x + 2400 = 120x + x^2 + 20x
x^2 + 20x - 2400 = 0
x^2 + 60x - 40x - 2400 = 0
x(x+60) - 40(x+60) = 0
x = 40,-60
As speed cannot be negative,
x=40km/hr
Speed of passenger train = x= 40km/hr
Speed of express train = y = x+20
= 40+20
= 60km/hr
Average speed of both trains = (x+y)/2
= (40+60)/2
=50km/hr
Answer:
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