please solve this above question
Answers
Given:
> x = 5
• We have to evaluate the given expression and find the value of x.
> x = x++ * 2 + 3 * --x
> x = 5 * 2 + 3 * --x (x remains 5, post-increment)
> x = 5 * 2 + 3 * --x (x becomes 6)
> x = 5 * 2 + 3 * 5 (x becomes 5, pre-decrement)
> x = 10 + 15
> x = 25
So, the final value of x is 25. (Answer)
Given:
> a = 2
> b = 3
• We have to evaluate the given expression and find out the value of x.
> x = a++ + ((++b) / 2)
> x = 2 + ((++b) / 2) (a remains 2, post-increment)
> x = 2 + ((++b) / 2) (a becomes 3)
> x = 2 + (4 / 2) (b becomes 4, pre-increment)
> x = 2 + 2 (integer division, quotient is obtained)
> x = 4
So, the final value of x is 4. (Answer)
There are two types of increment/decrement operations.
- Post increment/decrement.
- Pre increment/decrement.
Post Increment/Decrement: Here, operation takes place first and then the value is incremented/decremented.
Example:
> int a = 2;
> int b = a++;
> b = 2
Now, a = 3.
Pre Increment/Decrement: Here, value is first increment/decrement and then the operation is carried out.
Example:
> int a = 2;
> int b = ++a;
> b = 3
Also, a = 3