Please solve this accurately.I will mark those as brainliest(If the answer is with step by step method).And I will spam the content which is not relevant to this.
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Answer:
nearest value of x+y is 10cm
Step-by-step explanation:
first we take ∆ADB and ∆EDF
∠ADB=∠EDF (Using vertical opposite angles property)
∠ABD=∠FED (Using alternate angles property)
∠BAD=∠EFD (Using alternate angles property)
∴ΔADB∼ΔEDF (By using Angle Side Angle criterion)
Now, the ratio of their corresponding sides is:
BD/DE = AB/FE
4/y = 6/10
y = 6.67 cm
Similarly, ΔADE∼ΔCDE (using Angle-Angle criterion)
DE/BE = DC/BA
6.67/10.67 = x/6
x = 3.75 cm
therefore x+y = 3.75 + 6.67 = 10.42
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