please solve this algebraic expression
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Answered by
1
Answer:
x=3, y=4
Step-by-step explanation:
2x+3y=18
= 2*3+3*4
= 6+12
=18
Answered by
2
Here is your answer
2x+3y=18
=> 2x= 18-3y
=> x= (18-3y)/2
when,
y=0
x= (18-3×0)/2
= 9
when,
y=2
x= (18-3×2)/2
= 6
when,
y= -2
x= {18- 3×(-2)}/2
= 12
HOPE IT IS USEFUL
2x+3y=18
=> 2x= 18-3y
=> x= (18-3y)/2
when,
y=0
x= (18-3×0)/2
= 9
when,
y=2
x= (18-3×2)/2
= 6
when,
y= -2
x= {18- 3×(-2)}/2
= 12
HOPE IT IS USEFUL
abhaygoel71:
you're welcome
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