Question

please solve this all fast pleasa​

Answer 1

1) In a polygon the sum of exterior angles is 360°

90°+60°+40°+90°+x° = 360°

280°+x = 360°

x = 360°-280°

x = 80°

2) Above formula used again

x°+85°+20°+89°+92° = 360°

x° + 286° = 360°

x° = 360°-286°

= 74°

3) Formula to find diagonals in a polygon is : n(n-3) /2 where n is no. of sided

Here in Pentagon there are 5 sides

so diagonals = 5(5-3) / 2 = 5×2/2 = 10/2 = 5 diagonals

4) Formula to find sum of interior angles of any polygon : (n-2) × 180° where n is no. of sided

In octagon there are 8 sides

So sum of interior angles = (8-2)×180° = 1080°

5) It can be solved in the manner of question given above

6) A nonagon has 6 sides

7) x+y+z = 180° ( sum of interior angles of polygon )

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Answer 2

$(i) \: 90° + 90° + 40° + 60 °+ x = 360°$

$\: \: \: \: \: \: 280 °+ x = 360°$

$\: \: \: \: \: \: x = 360° - 280°$

$\: \: \: \: \: \: \: \: \: = 80°$

$(ii) \: 85° + 89° + 92° + 20 °+ x = 360°$

$\: \: \: \: \: \: 286° + x = 360°$

$\: \: \: \: \: \: x = 360° - 286°$

$\: \: \: \: \: \: \: \: \: = 74°$

$2. \: There \: are \: six \: diagonals \: in \: pentagon$

$3. \: The \: sum \: of \: interior \: angles \: is \: 1080°$

$4. \: Sum \: of \: exterior \: angles \: in \: hexagon \: is \: \\720$

$5. \: Nonagon \: have \: nine \: sides$

$6.\:x+y+z=180°$

$Start \: following \: me. \: If \: this \: answer \: is \\ \: helpful \: so \: mark \: my \: answer \: as \\ \: brainliest \: answer.$