Question

Please solve this and answer quickly

Answer 1

Step-by-step explanation:

Here,

AB‖CD, t is the transversal.

Let ∠AOP = (2x+40)°

and, ∠DPO = (x+90)°

∴ ∠AOP = ∠DPO [ ∵ they are alternate angles ]

BTP,

$(2x + 40)° = (x + 90)° \\ => 2x + 40 = x + 90 \\ => 2x - x = 90 - 40 \\ => x = 50°$

HENCE, the value of $x$ is 50°.

Answer 2

$\huge{ \underline{ \bold{ᴀɴsᴡᴇʀ....{ \heartsuit}}}}$

Here,

AB‖CD, t is the transversal.

Let ∠AOP = (2x+40)°

and, ∠DPO = (x+90)°

∴ ∠AOP = ∠DPO [ ∵ they are alternate angles ]

BTP,

$$\begin{lgathered}(2x + 40)° = (x + 90)° \\ => 2x + 40 = x + 90 \\ => 2x - x = 90 - 40 \\ => x = 50°\end{lgathered}$$

HENCE, the value of $$x$$ is 50°.