Computer Science, asked by fahadk509p52gq8, 1 year ago

please solve this and please explain. ​

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Answers

Answered by Anonymous
2

Question :-

for(int i=0;i<3;I++)

{

for(int j=0;j<2;j++)

{

int number=(int)(Math.random*10);

System.out.println(number);

}

}

How many times the loop runs ?

Answer :-

The loop will run 9 times .

Explanation :-

The i-loop starts from 0 and runs till 2 .

0 , 1 , 2 and hence it runs 3 times .

The j-loop starts from 0 and runs till 1 .

0,1 and hence it runs 2 times .

Number of times the j-loop is executed = number of times the i-loop is executed × number of iterations of the j-loop .

Number of times the j-loop is executed = 2 × 3 = 6 .

Number of times the i-loop is executed = 3 .

Total number of times the loop is executed = 6 + 3 = 9 .

The answer will be 9 .

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