Question

please solve this
and tell me the answer
​

Answer 1

9A+8BO3 --------->3A3O4 +4B2O3

according to balance chemical equation.

1mole of BO3 required 1.125 mole of A to complete the reaction.so the limited reagent is A.

in stochiometric equation

$9a = 3a3o4$

molar ratio=1÷3

moles of A3O4 produced=1mole of A ×1 mole of A3O4÷3 mole of A = 1÷3

so the right answer is c

Answer 2

Answer:

1/3

Explanation:

first we will find out the limiting reagent

L.R.(A) = 1/9

L.R.(BO3) = 1/8

WITH THE HELP OF FORMULA OF LIMITING REAGENT WE GOT TO KNOW THAT "A" IS THE LIMITING REAGENT

NOW,

ALL CALCULATIONS WILL BE DONE WITH THE HELP OF THE REACTANT "A" AS IT IS THE LIMITING REAGENT.

9 MOLES OF "A" GIVES MOLES OF A3O4 = 3

SO, 1 MOLE OF "A" GIVES MOLE OF A3O4 = 3/9 = 1/3