Question

please solve this and write down clearly and explainly​

Answer 1

Question:

Subtract the sum of 9b² - 3c² and 2b² + bc + 2c² from the sum of 2b² - 2bc - c² and c² + 2bc - b².

Solution:

$\bold{\leadsto (2b² - 2bc - c² + c² + 2bc - b²)-(9b² - 3c² + 2b² + bc + 2c²)}$

$\bold{=(2b² - \cancel{2bc} - \cancel{c²} + \cancel{c²} + \cancel{2bc} - b²)-(9b² - 3c² + 2b² + bc + 2c²)}$

$\bold{=(b²)-(11b² - c² + bc)}$

$\bold{=b² - 11b² + c² - bc}$

$=$$\bold{\red{10b² + c² - bc}}$