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Answer:
=OA 2 + OC 2
Step by step explanation:
LHS =OB
2
+OD
2
=(BQ
2
+OQ
2
)+(OS
2
+DS
2
) (Considering right angled triangles BQO and OSD)
But, BQ=AS and QC=DS
(BQ
2
+OQ
2
)+(OS
2
+DS
2
)
=(AS
2
+OQ
2
)+(OS
2
+QC
2
)
=(AS
2
+OS
2
)+(OQ
2
+QC
2
)
=OA
2
+OC
2
(Considering right angled triangles ASO and CQO)
= RHS
So, OB
2
+OD
2
=OA
2
+OC
2
proved.
i hope this helped please mark me the branliest!!
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