please solve this answer
its urgent guys!
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its just substituting,
sin2(30)=2sin(30)cos(30)
sin60=(2×1×√3)/(2×2)
√3/2=√3/2
cos3(30)=4cos^3(30)-3cos(30)
cos90=4(√3/2)^3-3(√3/2)
0=4(3√3/8)-3√3/2
0=3√3/2-3√3/2
0=0
sumikumar1714:
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hope it helps you........
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