Question

please solve this Answer this question​

Answer 1

Namastey ....

Hope it'll help

Answer 2

Question:

$\sf{If\:(x+\frac{1}{x})=3,\:find\: the\: value\:of\:x^2+\frac{1}{x^2}.}$

Solution :

$\sf{x+\frac{1}{x}=3}$

$\sf{x^2+\frac{1}{x^2}}$

Use the identity : a²+b²=(a+b)²-2ab

$\implies\sf{(x+\frac{1}{x})^2-2.x.\frac{1}{x}}$

Put $\sf{x+\frac{1}{x}=3}$ .

$\implies\sf{(3)^2-2}$

$\implies\sf{9-2}$

$\implies\sf{7}$

Therefore,

$\sf{The\: value\:of\:x^2+\frac{1}{x^2}\:is\:7.}$

_______________________

More identities :-

• (a+b)² = a² + 2ab + b²

• (a-b)² = a² - 2ab + b²

• a² - b² = (a+b) (a-b)

• (a+b)² + (a-b)² = 2(a² + b² )

• (a+b)² - (a-b)² = 4ab

_______________________