please solve this anyone
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sin²63= cos²(90-27)=cos²27
cos²17=sin²(90-73)=sin²73
cos²27+sin²27/sin²73 + cos²73
=1/1=1. by using the identity sin²a + cos²a= 1
cos²17=sin²(90-73)=sin²73
cos²27+sin²27/sin²73 + cos²73
=1/1=1. by using the identity sin²a + cos²a= 1
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