Math, asked by TANU81, 10 months ago

#Please solve this asap

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Answered by Rajshuklakld

Solution:-

Let the vectors be

VectorA=3i-2j+k,VectorB=i-3j+5k,VectorC=2i+j-4k

let us take out the dot product of VectorA and Vector C

VectorA.VectorC=3×2-2×1+4×1=0....i)

Also,we know that

A.B=abcos∅

dot product will be 0 only if ∅=90,

as in eqaution i) we are getting dot product 0,

so,we can say

VectorA is perpendicular to VectorC......ii)

magnitude of VectorA=(9+4+1)^1/2=√14

magnitude of VectorB=(1+9+25)^1/2=√35

magnitude of VectorC=(4+1+16)^1/2=√21

A^2+B^2=(√14)^2+(√21)^2=35=C^2

A^2+B^2=C^3.......ii)

this is following Pythagoras theorem

so,from equation i) and ii) we can say that they will form right angled triangle

Answered by Anonymous

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