please solve this asap
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Answered by
1
Answer:
A) 50°
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Answered by
1
Answer:
∠POA = 50°
Step-by-step explanation:
Given,
If tangents PA and PB from a point P to a circle with center O are inclined to each other at angle of 80°.
To Find:
∠POA = ?
Solution:
In ΔPOA and ΔPOB,
==> ∠POA = ∠PBO
==> OA = OB(radii of circle)
==> OP = OP(Common)
∴ ΔPOA ≅ ΔPOB[SSS congruency]
==> ∠OPA = ∠OPB
==> ∠OPA = ∠OPB = 40°
In ΔPAO,
∠APO + ∠POA + ∠OAP = 180°
==> 40° + ∠POA + 90° = 180°
==> ∠POA = 180° - 130°
==> ∠POA = 50°
Result:
∠POA = 50°
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