Question

please solve this asap...50 points for those who gives correct answers​

Answer 1

1.

By using the first equation of motion:

V =u +at    

Here initial velocity is zero "0"

Put the values.

V = 0 + gt   (since g = 9.8 m/s2)

V = gt = 9.8 x 2.6  

         = 25.48 m/s  

Now find the distance by using the 2nd equation of motion.

S = ut+(1/2)at2       (Since u = o)

S = (1/2)gt2      

S= (1/2) x 9.8 x (2.6)2

S= 9.8 x 6.76 /2

S = 66.248 / 2

S= 33. 124 m

2.

Here, initial velocity is u=18.5m/s and final velocity is v=46.1m/s

Time taken t=2.47s

If a be the acceleration of the car.

Using v=u+at,

46.1=18.5+a(2.47)

⟹ a=11.17m/s

2

If d be the distance traveled by car.

Using formula v

2

−u

2

=2ad,

(46.1)

2

−(18.5)

2

=2(11.17)d

⟹ d=79.8m

Answer 2

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