Question

Please solve this ASAP
and plese don't post fake answer ​

Answer 1

Answer:

Mate I Have Done The Correct Solution For You..

Step-by-step explanation:

Hope it Helps uh in your studies..

Thank you..❤️

Answer 2

Question

$\sf\large \displaystyle \int \dfrac{ {e}^{5log_{e}x} - {e}^{4log_{e}x} }{ {e}^{3log_{e}x}- {e}^{2log_{e}x} }$

$\huge\bold{\gray{\sf{Answer:}}}$

$\bold{Explanation:}$

$\sf\large= > \displaystyle \int \dfrac{ {e}^{5log_{e}x} - {e}^{4log_{e}x} }{ {e}^{3log_{e}x}- {e}^{2log_{e}x} }$

$\sf\large\boxed{mlogn = {logn}^{m}}$

$\sf\large= >\displaystyle \int \dfrac{ {e}^{log {x}^{5} } - {e}^{log {x}^{4} } }{ {e}^{log {x}^{3} } - {e}^{log {x}^{2} } } dx$

$\sf\large= > \displaystyle \int \dfrac{ {x}^{5} - {x}^{4} }{ {x}^{3} - {x}^{2} } dx$

$\large= >\displaystyle \int \dfrac{ {x}^{4} (x - 1)}{ {x}^{2}(x - 1) } dx$

$\large= > \displaystyle \int \dfrac{ {x}^{4} }{ {x}^{2} } = \int {x}^{2} dx$

$\sf\boxed{{x}^{n} dx = \dfrac{ {x}^{n + 1} }{n + 1} + c}$

$\sf\large\bold{\red{= \dfrac{ {x}^{3} }{3} + c}}$