Math, asked by Sheel05, 1 year ago

Please solve this ASAP with full process

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Answered by AshCroft
0

(a-b)³ = a³-b³-3ab(a-b)

⇒(2a-4b)³ = (2a)³-(4b)³-3(2a)(4b)(2a-4b)

   (1)³         = 8a³-64b³-24ab(1)

   1             = 8a³-64b³-24(2)

⇒ 1+48   = 8a³+64b³= 49

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