Question

please solve this brainliest

Answer 1

hey there....

here is ur answer...

first lets make the bases equal....

16 can be written as

${4}^{2}$

64 can be written as

${4}^{3}$
so the whole equation will be

$({ {4}^{2} })^{2x +3 } = {( {4}^{3} )}^{x + 3}$

we will have to multiply

2 and 2x+3 , 3 and x+3

it will be

4x+6 and 3x+9

if we do this we get...

${4}^{4x + 6} = {4}^{3x + 9}$

so basically

4x+6=3x+9

x = 3

they are asking to find...

${4}^{2x - 2}$

x is 3

so just substitute this...

we get...

${4}^{4}$

so the answer is 256.

hope this helps!

option (b)

Answer 2

Hey there
Plzz see the attached image

Hope it helps u !