Question

please solve this by pic​

Answer 1

Step-by-step explanation:

Distance covered by Car A = 50Km

Time taken by Car A = 30minutes

$Speed \: of \: Car \: A = \frac{Distance \: covered \: by \: Car \: A}{Time \: taken \: by \: Car \: A} \\ = \frac{50}{30} \\ = \frac{5}{3} km {h}^{ - 1}$

Distance covered by Car B = 5Km

Time taken by Car B = 2minutes

$Speed \: of \: Car \: B= \frac{Distance \: covered \: by \: Car \: B}{Time \: taken \: by \: Car \: B} \\ = \frac{5}{2} km {h}^{ - 1}$

$speed \: of \: car \: a = \frac{5}{3} km \: {h}^{ - 1} \\ speed \: of \: car \: b = \frac{5}{2} km \: {h}^{ - 1} \\ difference = \frac{5}{2} - \frac{5}{3} \\ = \frac{5(3)}{2(3)} - \frac{5(2)}{3(2)} \\ = \frac{15}{6} - \frac{10}{6} \\ = \frac{5}{6} \\ \\ thus \:car \: b \: is \: faster \: than \: \\ a \: \: by \: \: \frac{5}{6} km \: {h}^{ - 1}$

Answer 2

Answer:

Distance covered by Car A = 50Km

Time taken by Car A = 30minutes

Distance covered by Car B = 5Km

Time taken by Car B = 2minutes

Step-by-step explanation: