Math, asked by anyeshakoley3, 1 day ago

please solve this

Class 10th Arithmetic Progression​

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Answered by ՏʍɑɾեíҽƓմɾƖ
11

Saving 1st  year   =  Rs 20000

increased his yearly savings by Rs 5,000 each year.

Hence this is an AP

a = 20000

d = 5000

Class XII   -  

n = 12

an = a + (n-1)d

amount in 12 th class  = 20000 + (12 - 1) 5000 = 75000 Rs

Rs 75000  in class XII

Class X   -  

n = 10

20000 + (10 - 1)(5000) = Rs 65000

Rs 65000  in class X

Answered by Rina86169
1

Answer:

Saving 1st  year   =  Rs 20000

increased his yearly savings by Rs 5,000 each year.

Hence this is an AP

a = 20000

d = 5000

Class XII   -  

n = 12

an = a + (n-1)d

amount in 12 th class  = 20000 + (12 - 1) 5000 = 75000 Rs

Rs 75000  in class XII

Class X   -  

n = 10

20000 + (10 - 1)(5000) = Rs 65000

Rs 65000  in class X

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