please solve this correctly
25th sums
Attachments:
Answers
Answered by
9
Given : /_ A = X° , /_B = ( 3X - 2 )° and /_ C = Y°.
Also given that : /_ C - /_ B = 9°
Y° - ( 3X - 2 )° = 9
Y° - 3X + 2 = 9°
Y° = ( 9° + 3X - 2° )
Y° = ( 3X + 7)°
/_ C = Y° = ( 3X + 7 )°
As we know that Sum of all three Angles of a triangle is always equal to 180°.
So,
/_ A + /_ B + /_ C = 180°
X° + 3X - 2 + 3X + 7 = 180°
7X° + 5 = 180°
7X° = 180° - 5°
7X° = 175°
X° = 25°
Therefore,
/_ A = X° = 25°
/_ B = 3X - 2 = 3 × 25 - 2 = 73°
And,
/_ C = 3X + 7 = 3 × 25 + 7 = 82°.
Also given that : /_ C - /_ B = 9°
Y° - ( 3X - 2 )° = 9
Y° - 3X + 2 = 9°
Y° = ( 9° + 3X - 2° )
Y° = ( 3X + 7)°
/_ C = Y° = ( 3X + 7 )°
As we know that Sum of all three Angles of a triangle is always equal to 180°.
So,
/_ A + /_ B + /_ C = 180°
X° + 3X - 2 + 3X + 7 = 180°
7X° + 5 = 180°
7X° = 180° - 5°
7X° = 175°
X° = 25°
Therefore,
/_ A = X° = 25°
/_ B = 3X - 2 = 3 × 25 - 2 = 73°
And,
/_ C = 3X + 7 = 3 × 25 + 7 = 82°.
chanchal1966:
correct answer is 82
Similar questions