Question

Please solve this correctly​

Answer 1

Answer:

(a) x = 3

⇒ 3x(4x - 5) + 3

⇒ 3 × 3(4 × 3 - 5) + 3 [put the value of x = 3]

⇒ 9(12-5 )+ 3

⇒ 9 × 7 + 3

⇒ 63 + 3

⇒ 66

Now,

(b) x = \bf \frac{1}{2}

2

1

⇒ 3x(4x - 5) + 3

⇒ 3 × \bf \frac{1}{2}

2

1

(4 × \bf \frac{1}{2}

2

1

- 5) + 3 [pu the value of x = \bf \frac{1}{2}

2

1

⇒ \bf \frac{3}{2}

2

3

(2 - 5) + 3

⇒ \bf \frac{3}{2}

2

3

(-3) + 3

⇒ \bf \frac{-9}{2}

2

−9

+ 3

⇒ \bf \frac{-9 + 6}{2}

2

−9+6

⇒ \bf \frac{-3}{2}

2

−3

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Answer 2

Step-by-step explanation:

3x(4x-5) +3

=12x²-15x+3

1). for x=3

=12×3²-15×3+3

=12×9-45+3

=108-42

=66

2). for x= 1/2

= 12×(1/2)²-15×(1/2)+3

=12×(1/4)-15/2 +3

=3-15/2+3

= -15/2