Question

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Answer 1

Answer:

b²-4ac

x²+4x-1

4²-4×1×(-1)

16+4=20

D=20

x=-b±√D/2a.

x=-4+2√5/2 |. x=-4-2√5/2

x=-2+2√5,-2-2√5

Answer 2

Answer:

for QE, x^2 + 4x- 1 = 0

D = b^2 - 4ac = (4)^2 - 4(1)(-1)

= 16 + 4 = 20

Thus,

-b ± rootD/ 2a

= -4 ± root20/ 2×1

= -4 + 4root5/ 2 OR

- 4 - 4root5/ 2

= - 1 ± root5 would be your first answer.

Similarly,you will get the root of other two equations.

Hope it helps you.

please mark my answer as brainliest.