please solve this equation fast
Attachments:
Answers
Answered by
3
Answer :
The required term be
= ( 3x² - 4y² + 5xy - 20 ) - ( - x² - y² + 6xy + 20 )
= 3x² - 4y² + 5xy - 20 + x² + y² - 6xy - 20
= ( 3 + 1 ) x² + ( - 4 + 1 ) y² + ( 5 - 6 ) xy + ( - 20 - 20 )
= 4x² - 3y² - xy - 40
#MarkAsBrainliest
The required term be
= ( 3x² - 4y² + 5xy - 20 ) - ( - x² - y² + 6xy + 20 )
= 3x² - 4y² + 5xy - 20 + x² + y² - 6xy - 20
= ( 3 + 1 ) x² + ( - 4 + 1 ) y² + ( 5 - 6 ) xy + ( - 20 - 20 )
= 4x² - 3y² - xy - 40
#MarkAsBrainliest
Similar questions