Question

please solve this equation its urgent 5(2x-1)+3(4x+3)/4x-1=5​

Answer 1

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$5(2x - 1) + \frac{3(4x + 3)}{4x - 1} = 5 \\ \\ 10x - 5 + \frac{12x + 9}{4x - 1} = 5 \\ \\ 10x + \frac{12x + 9}{4x - 1} = 10 \\ \\ \frac{10x(4x - 1) + 12x + 9}{4x - 1} = 10 \\ \\ 40 {x}^{2} - 10x + 12x + 9 = 10(4x - 1) \\ \\ 40 {x}^{2} + 2x + 9 = 40x - 10 \\ \\ 40 {x}^{2} - 38x = - 19$

Answer 2

Answer:

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